Comments on: Hi, my name is Jesse and I abuse list comprehensions.

By: Giulio Piancastelli

Giulio Piancastelli — Sun, 30 Mar 2008 00:51:12 +0000

I could argue that the first has a typo, although you’d need to execute it.

By: Giulio Piancastelli

Giulio Piancastelli — Sat, 29 Mar 2008 20:51:12 +0000

I could argue that the first has a typo, although you’d need to execute it.

By: Doug Hellmann

Doug Hellmann — Fri, 28 Mar 2008 22:30:36 +0000

I find list comprehensions easier to grok when they are written on multiple lines.

[ value
for item in sequence
(if condition)
]

By: Justin

Justin — Fri, 28 Mar 2008 21:06:21 +0000

or

return ',',join( '{{whizbang|%(foo)s}}' % i for i in myDict[keyname] )

By: jnoller

jnoller — Fri, 28 Mar 2008 18:22:27 +0000

[q for q in [z for z in [y for y in [x for x in mylist]]]]

mmmm. Delicious. Jam a lambda and a couple of .method() calls on the objects being iterated through and it will be complete.

By: jnoller

jnoller — Fri, 28 Mar 2008 18:21:26 +0000

Still not convoluted enough

By: Martin

Martin — Fri, 28 Mar 2008 18:10:19 +0000

The following expressions are equivalent, which one would you choose? ;-)

mylist
[x for x in mylist]
[y for y in [x for x in mylist]]
[z for z in [y for y in [x for x in mylist]]]
[q for q in [z for z in [y for y in [x for x in mylist]]]]

ok... you get the point. (Strictly speaking they are not complely equivalent since the first of them doesn't yield a copy of the list but is rather a reference to the original)

By: Virgil Dupras

Virgil Dupras — Fri, 28 Mar 2008 17:58:43 +0000

What about:

whizzes = (d['foo'] for d in myDict[keyname])
return ','.join('{{whizbang |%s}}' % whiz for whiz in whizzes)

By: mike

mike — Fri, 28 Mar 2008 17:08:39 +0000

not to mention return ‘,’.join([‘{{whizbang|%s}}’ % v for v in myDict[keyname].values()])

By: jnoller

jnoller — Fri, 28 Mar 2008 16:18:02 +0000

Hmm, good question. I’ll have to try that one out, although I still have to go with option 3